Java Program to Find Largest Number in an Array

Finding the largest number in an array is a common Java interview question that helps test understanding of arrays, loops, and logical thinking.

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🔹 Approach

1. Assume the first element as the largest number.

2. Traverse the array using a loop.

3. Compare each element with the current largest value.

4. Update the largest value when a bigger number is found.

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🔹 Java Program

public class LargestNumber {

    public static void main(String[] args) {

        int[] numbers = {12, 45, 7, 89, 34, 67};
        int largest = numbers[0];

        for(int i = 1; i < numbers.length; i++) {
            if(numbers[i] > largest) {
                largest = numbers[i];
            }
        }

        System.out.println("Largest Number = " + largest);
    }
}

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🔹 Output

Largest Number = 89

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🔹 Using Enhanced For Loop (Alternative)

int[] numbers = {12, 45, 7, 89, 34, 67};
int largest = numbers[0];

for(int num : numbers) {
    if(num > largest) {
        largest = num;
    }
}
System.out.println("Largest Number = " + largest);

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✅ Conclusion

This program demonstrates how to iterate through arrays and compare values efficiently. It is one of the most frequently asked logical questions in Java interviews.

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